General Linear Least Squares

The linear in linear least squares refers to how the parameters appear in the fitting function, \(Y\). So something of the form:

\[Y(x; \{a_j\}) = \sum_{j=1}^M a_j \varphi_j(x)\]

is still linear in the \(\{a_j\}\), even if the basis functions \(\{\varphi_j\}\) are nonlinear. For example:

\[Y(x; \{a_j\}) = a_1 + a_2 x + a_3 x^2\]

is linear in the fit parameters \(\{ a_j\}\), The basis functions in this case are:

\[\begin{align*} \varphi_1 &= 1 \\ \varphi_2 &= x \\ \varphi_3 &= x^2 \end{align*}\]

We can apply the same technique we just did for fitting to a line for this general case.

The discussion in Garcia, Numerical Methods for Physics, gives a nice overview, which we loosely follow here.

Our \(\chi^2\) is:

\[\chi^2(\{a_j\}) = \sum_{i=1}^N \frac{(Y(x_i; \{a_j\}) - y_i)^2}{\sigma_i^2} = \sum_{i=1}^N \frac{1}{\sigma_i^2} \left [\left (\sum_{j=1}^M a_j \varphi_j(x_i)\right ) - y_i \right ]^2\]

We can differentiate it with respect to one of the parameters, \(a_k\):

\[\begin{align*} \frac{\partial \chi^2}{\partial a_k} &= \frac{\partial}{\partial a_k} \sum_{i=1}^N \frac{1}{\sigma_i^2} \left [\left (\sum_{j=1}^M a_j \varphi_j(x_i)\right ) - y_i \right ]^2 \\ &= \sum_{i=1}^N \frac{1}{\sigma_i^2} \frac{\partial}{\partial a_k} \left [\left (\sum_{j=1}^M a_j \varphi_j(x_i)\right ) - y_i \right ]^2 \\ &= 2 \sum_{i=1}^N \frac{1}{\sigma_i^2} \left [\left (\sum_{j=1}^M a_j \varphi_j(x_i)\right ) - y_i \right ] \varphi_k(x_i) = 0 \end{align*}\]

We can now rewrite this as:

\[\sum_{i=1}^N \sum_{j=1}^M a_j \frac{\varphi_j(x_i) \varphi_k(x_i)}{\sigma_i^2} = \sum_{i=1}^N \frac{y_i \varphi_k(x_i)}{\sigma_i^2}\]

We define the \(N\times M\) design matrix as

\[A_{ij} = \frac{\varphi_j(x_i)}{\sigma_i}\]

and the source as:

\[b_i = \frac{y_i}{\sigma_i}\]

our system is:

\[\sum_{i=1}^N \sum_{j=1}^M A_{ik} A_{ij} a_j = \sum_{i=1}^N A_{ik} b_i\]

which, by looking at which indices contract, gives us the linear system:

\[{\bf A}^\intercal {\bf A} {\bf a} = {\bf A}^\intercal {\bf b}\]

where \({\bf A}^\intercal {\bf A}\) is an \(M\times M\) matrix.

The procedure we described above is sometimes called ordinary least squares.

Parabolic Fit

Let’s consider fitting to a function:

\[Y(x; \{a_j\}) = \sum_{j=1}^M a_j x^{j-1}\]

for \(M = 3\), this is:

\[Y(x) = a_1 + a_2 x + a_3 x^2\]

If we have 10 data points, \(x_1, \ldots, x_{10}\), then our matrix \({\bf A}\) will take the form:

\[\begin{split}{\bf A} = \left (\begin{array}{ccc} 1/\sigma_1 & x_1/\sigma_1 & x_1^2/\sigma1 \\ 1/\sigma_2 & x_2/\sigma_2 & x_2^2/\sigma_2 \\ \vdots & \vdots & \vdots \\ 1/\sigma_{10} & x_{10}/\sigma_{10} & x_{10}^2/\sigma_{10} \end{array} \right )\end{split}\]

import numpy as np
import matplotlib.pyplot as plt

Let’s first write a function that takes an \(x_i\) and returns the entries in a row of \({\bf A}\)

def basis(x, M=3):
    """ the basis function for the fit, x**n"""
    
    j = np.arange(M)
    return x**j

Now we’ll write a function that takes our data and errors and sets up the linear system \({\bf A}^\intercal {\bf A} {\bf a} = {\bf A}^\intercal {\bf b}\) and solves it.

def general_regression(x, y, yerr, M):
    """ here, M is the number of fitting parameters.  We will fit to
        a function that is linear in the a's, using the basis functions
        x**j """

    N = len(x)

    # construct the design matrix -- A_{ij} = Y_j(x_i)/sigma_i -- this is
    # N x M.  Each row corresponds to a single data point, x_i, y_i
    A = np.zeros((N, M), dtype=np.float64)

    for i in range(N):
        A[i,:] = basis(x[i], M) / yerr[i]

    # construct the MxM matrix for the linear system, A^T A:
    ATA = np.transpose(A) @ A

    print("condition number of A^T A:", np.linalg.cond(ATA))

    # construct the RHS
    b = np.transpose(A) @ (y / yerr)

    # solve the system
    a = np.linalg.solve(ATA, b)

    # return the chisq
    chisq = 0
    for i in range(N):
        chisq += (np.sum(a*basis(x[i], M)) - y[i])**2 / yerr[i]**2

    chisq /= N-M

    return a, chisq

Finally, we’ll make up some experiment data that follows a parabola, but with a perturbation.

def y_experiment2(a1, a2, a3, sigma, x):
    """ return the experimental data and error in a quadratic +
    random fashion, with a1, a2, a3 the coefficients of the
    quadratic and sigma is scale of the error.  This will be
    poorly matched to a linear fit for a3 != 0 """

    N = len(x)
    r = sigma * np.random.randn(N)
    
    y = a1 + a2*x + a3*x*x + r

    return y, np.abs(r)

N = 40
x = np.linspace(0, 100.0, N)

# one-sigma error
sigma = 8.0

y, yerr = y_experiment2(2.0, 1.50, -0.02, sigma, x)

fig, ax = plt.subplots()

ax.errorbar(x, y, yerr=yerr, fmt="o")

<ErrorbarContainer object of 3 artists>

Now let’s do the fit of a parabola. Along the way, we’ll print out the condition number of the matrix \({\bf A}^\intercal{\bf A}\).

# do the regression with M = 3 (1, x, x^2)
M = 3
a, chisq = general_regression(x, y, yerr, M)

condition number of A^T A: 68785489.166329

Notice that the condition number is quite large!

ax.plot(x, a[0] + a[1]*x + a[2]*x*x)
fig

Higher order fit

fig, ax = plt.subplots()
M = 10
a, chisq = general_regression(x, y, yerr, M)
yfit = np.zeros((len(x)), dtype=x.dtype)
for i in range(N):
    base = basis(x[i], M)
    yfit[i] = np.sum(a*base)

ax.errorbar(x, y, yerr=yerr, fmt="o")
ax.plot(x, yfit)

condition number of A^T A: 4.941874983114367e+34

[<matplotlib.lines.Line2D at 0x7fa5e8629fc0>]

The \(M = 10\) polynomial fits, but the condition number is large. It is not clear that going higher order here is wise.

Fitting and condition number

It can be shown that if your basis function is orthonormal in the interval you are fitting over, then the condition number of the matrix \({\bf A}^\intercal {\bf A}\) will be much lower. For example, it we fit to the interval \([-1, 1]\), then the Legendre polynomials are a good basis.

The text by Yakowitz & Szidarovszky has a good discussion on this.

Errors in the fitting parameters

It can be shown that the errors in the fitting parameters are:

\[\sigma_{a_j} = \sqrt{C_{jj}}\]

where

\[{\bf C} = ({\bf A}^\intercal {\bf A})^{-1}\]

is the covariance matrix.